10x^2-9x+27=0

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Solution for 10x^2-9x+27=0 equation:


Simplifying
10x2 + -9x + 27 = 0

Reorder the terms:
27 + -9x + 10x2 = 0

Solving
27 + -9x + 10x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
10 the coefficient of the squared term: 

Divide each side by '10'.
2.7 + -0.9x + x2 = 0

Move the constant term to the right:

Add '-2.7' to each side of the equation.
2.7 + -0.9x + -2.7 + x2 = 0 + -2.7

Reorder the terms:
2.7 + -2.7 + -0.9x + x2 = 0 + -2.7

Combine like terms: 2.7 + -2.7 = 0.0
0.0 + -0.9x + x2 = 0 + -2.7
-0.9x + x2 = 0 + -2.7

Combine like terms: 0 + -2.7 = -2.7
-0.9x + x2 = -2.7

The x term is -0.9x.  Take half its coefficient (-0.45).
Square it (0.2025) and add it to both sides.

Add '0.2025' to each side of the equation.
-0.9x + 0.2025 + x2 = -2.7 + 0.2025

Reorder the terms:
0.2025 + -0.9x + x2 = -2.7 + 0.2025

Combine like terms: -2.7 + 0.2025 = -2.4975
0.2025 + -0.9x + x2 = -2.4975

Factor a perfect square on the left side:
(x + -0.45)(x + -0.45) = -2.4975

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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